Quantitative Ability and Data Interpretation are calculation-intensive and tricky sections of XAT exam. In the recent years, there has been a reduction in the number of these questions of both segments. Yet, their overall weightage remains high in the exam. So, you must have a sound strategy to sail through these critical sections.

In this article, we will discuss the nature of questions generally asked in the XAT Quantitative Ability & Data Interpretation section and ways to solve them efficiently.

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The major areas for XAT Quant section include: Algebra and Functions, Number System, Probability, Mixtures, Geometry, Co-ordinate Geometry, Arithmetic Sequences, Tables, Charts, Multiple Graphs, Percentages, Profit and Loss, Interest, Averages, Logarithm, etc. Within these, XAT examiners have focused on areas of Geometry, Algebra and Number Systems along with questions from Tables and Multiple graphs.

You should learn and practice the basic concepts of all the major topics of Quant with a special focus on the above-mentioned areas. Let us take a look at a couple of questions that appeared in previous year XAT exams:

As you can see, just having the basic knowledge of Arithmetic Progression (A.P) is sufficient to answer this question.

Solution: T_{n}= a + (n - 1) d

- 100 = - 64 + (n - 1)( - 2)

Solving this we get, n = 19

S _{19} = 19/2 [(-64)+(-100)]

19/2 X(-164) = 19 x (-82) = - 1558

**Q. 2. A teacher noticed a strange distribution of marks in the exam. There were only three distinct scores: 6, 8 and 20. The mode of the distribution was 8. The sum of the scores of all the students was 504. The number of students in most populated category was equal to the sum of the number of students with lowest score and twice the number of students with the highest score. What was the total number of students in the class? (XAT previous year)**

Now, in order to answer this question, having the basic knowledge of averages is sufficient.

Solution: Let students with 6 marks be z, 8 marks be x, 20 marks be y,

So we get the equation as

8x + 6z + 20y = 504....(i)

and x = z + 2y.... (ii)

Putting the value of x from (ii) you get

8z + 16y + 6z + 20y = 504

⇒ 14z + 36y = 504

⇒ 7z + 18y = 252

Only value of y satisfying this is y = 7 ⇒ z = 18 and x = 32.

Therefore, Total = 7 + 18 + 32 = 57

- 128 square meters
- 154 square meters
- 162 square meters
- 172 square meters
- None of the above

Solution: Folded part as shown in the first figure is a triangle - a right triangle. The two perpendicular sides of the right triangle measure 6m each. So, the triangle is a right isosceles triangle. When unfolded, the folded area becomes a square as shown in the following figure:

The side of the square will be the width of the larger rectangle and is therefore, 6m.

Area of the square = 6 * 6 = 36 sq.m

When folded, only the area of the right triangle gets counted. However, when unfolded the area of square gets counted. The square comprises two congruent right triangles.

In essence, when folded only half a square is counted. When unfolded the entire square gets counted.

The area of the rectangle when unfolded = area of the rectangle when folded + area of half a square.

So area after unfolding= 144 + 18 = 162 sq.m.

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In XAT, the perceived level of difficulty of DI questions is on the higher side. XAT examiners provide data either in statement form or in the form of complex diagrams. While these problems appear tough at first, we suggest that you carefully go through each problem. You will see invariably that the questions are not as tough as they appear.

Do not judge the level of the questions from the complexity of the graph only. We suggest that you attempt questions from every set individually i.e. it is not necessary to attempt all the questions of a particular set.

**Study the graph below and answer the questions 1--3 that follow: **

This graph depicts the last eight years’ annual salaries (in Rs. (lacs.)) offered to students during campus placement. Every year 100 students go through placement process. However, at least one of them fails to get placed. The salaries of all unplaced students are marked zero and represented in the graph.

**Q.1.** In which year were a maximum number of students offered salaries between Rs.20 to Rs. 30 lacs (both inclusive)?

- 2008
- 2009
- 2010
- 2012
- Cannot be determined

At least 25% of the students definitely got salaries between 20-30 lacs in years 2008, 2010 and 2012. However, the graphs do not tell the actual salaries. Hence, no comment can be made on the number of students within a particular salary range.

Option E is the correct answer.

Option E is the correct answer.

- 2009, 2010
- 2012, 2014
- 2009, 2010, 2012
- 2009, 2012, 2014
- 2009, 2010, 2012, 2014

It is clear from the above table that in 2012 and 2014, the median of existing year is higher than 1.6 times mean of previous years. Hence the correct answer is: 2012 and 2014.

Option B is the correct answer.

Year | 2008 | 2009 | 2010 | 2011 | 2012 | 2013 | 2014 | 2015 |

Number without job offers | 9 | 5 | 20 | 2 | 2 | 4 | 15 | 2 |

- 3
- 4
- 5
- 6
- Cannot be solved without additional information.

The answer can be found based on the table given:

New Average Salary = (Old Average Salary)×100/(100-students without jobs)

Based on the additional information, the new average would be higher than the graph average of all the years. During two years old averages were already higher than median (2008 and 2013). With 20 students taken out, the new average salary for 2010 would jump to 23.4, which is clearly higher than median salary of 22. Similarly, the value of 2013 would jump further by at least one hence making new average definitely higher than existing median. In 2008, even the existing mean is visibly higher than median. Hence, the three 3 years are: (2008, 2010, and 2013).

Option A is the correct answer.

New Average Salary = (Old Average Salary)×100/(100-students without jobs)

Based on the additional information, the new average would be higher than the graph average of all the years. During two years old averages were already higher than median (2008 and 2013). With 20 students taken out, the new average salary for 2010 would jump to 23.4, which is clearly higher than median salary of 22. Similarly, the value of 2013 would jump further by at least one hence making new average definitely higher than existing median. In 2008, even the existing mean is visibly higher than median. Hence, the three 3 years are: (2008, 2010, and 2013).

Option A is the correct answer.

The level of difficulty of the Quant and DI section varies from moderate to tough. Besides, you will find indirect usage of the various mathematical concepts in the exam. In the past, the exam has seen some easy questions based on mathematical logic. But these easy questions or sitters have to be carefully selected, as the language used in questions is sometimes complex and can pose a challenge.

At the same time, the total number of questions in this paper is lesser in comparison to other exams. Hence, an optimum use of the available time can make you perform better in this exam. Compared to other exams like MAT, SNAP, CMAT, etc. the overall difficulty level of XAT Quant and DI section is on the higher side. In order to score well in the exam, you need to develop a strategy for the section. A few things you should keep in mind are:

- Be completely aware of your strong and weak areas. On the basis of this, decide the problem types you will solve first in the exam.
- Be careful of the amount of time you spend on particular problems. Remember, in order to maximize your scores, you need to manage your time well.
- Make sure you go through past year XAT exams in order to understand the types of questions asked in the exam.
- Solve maximum possible number of XAT Mock Tests to speed up calculation work as well to learn the art of selecting appropriate questions.

Lastly, regular practice of quant and DI questions along with in-depth analysis will help you crack XAT.